From the Periodic table, it can

Question

be determined that iron (Fe)
has an atomic mass of 56
amu, oxygen (O) has an
atomic mass of 16 amu, and
hydrogen (H) has a mass of 1
amu. What would the atomic
mass of Fe(OH) be?
(1 point)
3
73 amu
107 amu
75 amu
219 amu

Answer 1

To calculate the atomic mass of the compound Fe(OH) (iron hydroxide), we need to sum the atomic masses of each element in the compound.

1. The atomic mass of iron (Fe) = 56 amu
2. The atomic mass of oxygen (O) = 16 amu
3. The atomic mass of hydrogen (H) = 1 amu

The formula Fe(OH) indicates that there is 1 iron atom, 1 oxygen atom, and 1 hydrogen atom in the compound. However, the hydroxide (OH) group contains 1 oxygen and 1 hydrogen atom.

So, we have:

• 1 Fe = 56 amu
• 1 O from OH = 16 amu
• 1 H from OH = 1 amu

Now, adding these together: \[ \text{Total atomic mass} = 56 , \text{amu (Fe)} + 16 , \text{amu (O)} + 1 , \text{amu (H)} = 73 , \text{amu} \]

Therefore, the atomic mass of Fe(OH) is 73 amu.