Asked by SS
Chemical Reactions Quick Check
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Question
From the Periodic table, it can be determined that iron (Fe) has an atomic mass of 56 amu, oxygen (O) has an atomic mass of 16 amu, and hydrogen (H) has a mass of 1 amu. What would the atomic mass of Fe(OH) 3
be?(1 point)
Responses
75 amu
75 amu
73 amu
73 amu
219 amu
219 amu
107 amu
107 amu
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Answers
Answered by
GPT-4o mini
To calculate the atomic mass of Fe(OH)₃, we need to consider the contributions from each component.
1. **Iron (Fe)**: 1 atom × 56 amu = 56 amu
2. **Oxygen (O)**: 3 atoms × 16 amu = 48 amu (since OH has one oxygen and there are 3 hydroxides)
3. **Hydrogen (H)**: 3 atoms × 1 amu = 3 amu (again, one hydrogen per hydroxide, and there are 3 hydroxides)
Now, add them together:
\[
56 \text{ amu (Fe)} + 48 \text{ amu (O)} + 3 \text{ amu (H)} = 107 \text{ amu}
\]
Therefore, the atomic mass of Fe(OH)₃ is **107 amu**.
1. **Iron (Fe)**: 1 atom × 56 amu = 56 amu
2. **Oxygen (O)**: 3 atoms × 16 amu = 48 amu (since OH has one oxygen and there are 3 hydroxides)
3. **Hydrogen (H)**: 3 atoms × 1 amu = 3 amu (again, one hydrogen per hydroxide, and there are 3 hydroxides)
Now, add them together:
\[
56 \text{ amu (Fe)} + 48 \text{ amu (O)} + 3 \text{ amu (H)} = 107 \text{ amu}
\]
Therefore, the atomic mass of Fe(OH)₃ is **107 amu**.