Question

What is the simplest form of radical 1,200 over radical 50

Answer 1

To simplify \(\frac{\sqrt{1200}}{\sqrt{50}}\), we can combine the square roots:

\[
\frac{\sqrt{1200}}{\sqrt{50}} = \sqrt{\frac{1200}{50}}.
\]

Now, we calculate \(\frac{1200}{50}\):

\[
\frac{1200}{50} = 24.
\]

So, we have:

\[
\sqrt{\frac{1200}{50}} = \sqrt{24}.
\]

Next, we can simplify \(\sqrt{24}\). First, we factor \(24\):

\[
24 = 4 \times 6 = 4 \times (2 \times 3).
\]

Thus, we can rewrite \(\sqrt{24}\) as:

\[
\sqrt{24} = \sqrt{4 \times 6} = \sqrt{4} \times \sqrt{6} = 2\sqrt{6}.
\]

Therefore, the simplest form of \(\frac{\sqrt{1200}}{\sqrt{50}}\) is:

\[
\boxed{2\sqrt{6}}.
\]