Question

(fractions)
-1/3 + (5/9)

Answer 1

try again

Answer 2

To add the fractions \(-\frac{1}{3}\) and \(\frac{5}{9}\), we first need a common denominator. The simplest common denominator for 3 and 9 is 9.

1. Convert \(-\frac{1}{3}\) to a fraction with a denominator of 9:
\[
-\frac{1}{3} = -\frac{1 \times 3}{3 \times 3} = -\frac{3}{9}
\]

2. Now add the two fractions:
\[
-\frac{3}{9} + \frac{5}{9} = \frac{-3 + 5}{9} = \frac{2}{9}
\]

So, \(-\frac{1}{3} + \frac{5}{9} = \frac{2}{9}\).

Answer 3

Let's try the addition again step by step.

To add \(-\frac{1}{3}\) and \(\frac{5}{9}\), we need a common denominator.

1. **Identify the denominators**: The denominators are 3 and 9. The least common denominator (LCD) is 9.

2. **Convert \(-\frac{1}{3}\) to a fraction with a denominator of 9**:
\[
-\frac{1}{3} = -\frac{1 \times 3}{3 \times 3} = -\frac{3}{9}
\]

3. **Now add the two fractions**:
\[
-\frac{3}{9} + \frac{5}{9} = \frac{-3 + 5}{9} = \frac{2}{9}
\]

So the result of \(-\frac{1}{3} + \frac{5}{9}\) is indeed \(\frac{2}{9}\). If you have a specific point you want me to address or clarify, please let me know!