Hi! could anyone help me please, I have no idea how to this at all. I try to it but, the did not get the right answer. Thank for your help

Question

Oppositely charged parallel plates are separated by 5.34 mm. A potential difference of 600 V exists between the plates.
(a) What is the magnitude of the electric field between the plates?
___ N/C

(b) What is the magnitude of the force on an electron between the plates?
____ N

(c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.89 mm from the positive plate?
___ J

Answer 1

Did they mention the exact numbers of the charges of the parallel plates?

Answer 2

Field strength E times distance between plates = Voltage difference