To determine \( z_{\alpha/2} \) for a 94% confidence interval, we first need to find \( \alpha \), which represents the total area in the tails of the normal distribution.
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The confidence level is 94%, so: \[ \alpha = 1 - 0.94 = 0.06 \]
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Since the confidence interval is two-tailed, we split \( \alpha \) into two tails: \[ \frac{\alpha}{2} = \frac{0.06}{2} = 0.03 \]
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Next, we look for the \( z \)-score that corresponds to an area of \( 1 - 0.03 = 0.97 \) in the standard normal distribution.
You can use a standard normal distribution table or a calculator to find this value. The \( z \)-score that corresponds to an area of 0.97 is approximately:
\[ z_{0.03} \approx 1.881 \]
Thus, \( z_{\alpha/2} \) for a 94% confidence interval is approximately 1.881.