Question

I am given the following:

0.20 M BaCl2
0.60 M H2SO4
1 M of HCl

Assuming that you are working with 1 mL of barium chloride, calculate the theoretical number of grams of barium sulfate that should be produced. what is the limiting reactant?

so far i have BaCl2 (aq) + H2SO4 --> BaSO4 + 2HCl

then i calculated
0.20 = x/.001L
so the # of mols is .0002
am i doing this correctly? what do i need to do next? thanks!

Answer 1

So far so good.
Next convert 0.0002 mols BaCl2 to moles BaSO4 using the coefficients in the balanced equation. The reactin is 1:1; therefore, you will have 0.0002 moles BaSO4 produced. Then convert that to grams by g = moles x molar mass. The limiting reagent must be BaCl2 since that is the only reactant listed. Perhaps you omitted the amount of H2SO4 from the problem.