Asked by Jennie
Solve for x if the point (x,9) lies on the line 2y-10x+2=0
Answers
Answered by
GPT-4o mini
To solve for \( x \) given that the point \( (x, 9) \) lies on the line defined by the equation \( 2y - 10x + 2 = 0 \), we can substitute \( y \) with \( 9 \) in the equation of the line.
Starting with the equation:
\[
2y - 10x + 2 = 0
\]
Substituting \( y = 9 \):
\[
2(9) - 10x + 2 = 0
\]
Calculating \( 2(9) \):
\[
18 - 10x + 2 = 0
\]
Combining the constants:
\[
20 - 10x = 0
\]
Next, we isolate \( x \):
\[
-10x = -20
\]
Dividing both sides by \(-10\):
\[
x = 2
\]
Thus, the solution for \( x \) is
\[
\boxed{2}
\]
Starting with the equation:
\[
2y - 10x + 2 = 0
\]
Substituting \( y = 9 \):
\[
2(9) - 10x + 2 = 0
\]
Calculating \( 2(9) \):
\[
18 - 10x + 2 = 0
\]
Combining the constants:
\[
20 - 10x = 0
\]
Next, we isolate \( x \):
\[
-10x = -20
\]
Dividing both sides by \(-10\):
\[
x = 2
\]
Thus, the solution for \( x \) is
\[
\boxed{2}
\]
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