Asked by Kate
How do I solve this problem:
A particular wire has a current of 10A.
A) How many electrons pass a fixed point every 5 seconds?
B)If a wire has a radius of 2 x 10^(-3) m and the electron drift speed is 2.63 x 10^(-5) m/s, determine the number density of electrons in the wire.
The teacher posts the answers for us, so the answer for
A) 3.125 x 10^(20) e^(-)
B) 1.89 x 10^(29) e^(-)/ m^3
A particular wire has a current of 10A.
A) How many electrons pass a fixed point every 5 seconds?
B)If a wire has a radius of 2 x 10^(-3) m and the electron drift speed is 2.63 x 10^(-5) m/s, determine the number density of electrons in the wire.
The teacher posts the answers for us, so the answer for
A) 3.125 x 10^(20) e^(-)
B) 1.89 x 10^(29) e^(-)/ m^3
Answers
Answered by
drwls
It looks like you are switching names. Why?
A) Current (in Amperes) is charge passing by per second.
B) Current = (free electron number density)x (drift speed) x (cross sectional area)
Solve for the FREE electron density. (Electrons that remain attached to the nuclei of the conductor atoms are not included).
A) Current (in Amperes) is charge passing by per second.
B) Current = (free electron number density)x (drift speed) x (cross sectional area)
Solve for the FREE electron density. (Electrons that remain attached to the nuclei of the conductor atoms are not included).
Answered by
Kate
Thanks for the help! And BTW, I am not switching my name.
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