Question
A chemist prepares a solution of zinc nitrate (Za(NO.), by measuring out 3.8x 102 umol of zinc nitrate into a 350. ml volumetric flask and filing the fask to the mark with water
the mark with water.
Calculate the concentration in mol/L of the chemist's zinc nitrate solution. Be sure your answer has the correct number of significant digits.
the mark with water.
Calculate the concentration in mol/L of the chemist's zinc nitrate solution. Be sure your answer has the correct number of significant digits.
Answers
GPT 3.5
To calculate the concentration of the zinc nitrate solution, we first need to convert the given amount of zinc nitrate in micromoles to moles:
3.8 x 10^2 umol = 3.8 x 10^-4 mol
Next, we need to calculate the volume of the solution in liters by converting the volume of the volumetric flask from milliliters to liters:
350 ml = 0.350 L
Finally, we can calculate the concentration of the zinc nitrate solution by dividing the moles of zinc nitrate by the volume of the solution:
Concentration = 3.8 x 10^-4 mol / 0.350 L = 1.09 x 10^-3 mol/L
Therefore, the concentration of the chemist's zinc nitrate solution is 1.09 x 10^-3 mol/L.
3.8 x 10^2 umol = 3.8 x 10^-4 mol
Next, we need to calculate the volume of the solution in liters by converting the volume of the volumetric flask from milliliters to liters:
350 ml = 0.350 L
Finally, we can calculate the concentration of the zinc nitrate solution by dividing the moles of zinc nitrate by the volume of the solution:
Concentration = 3.8 x 10^-4 mol / 0.350 L = 1.09 x 10^-3 mol/L
Therefore, the concentration of the chemist's zinc nitrate solution is 1.09 x 10^-3 mol/L.