chemist prepares a solution of sodium nitrate (NaNO3) by measuring out 19. g of sodium nitrate into a 150. ml. volumetric flask and filling the flask to the lark with water.

Question

alculate the concentration in mol/L of the chemist's sodium nitrate solution. Be sure your answer has the correct number of significant digits.

Answer 1

To calculate the concentration in mol/L, we first need to find the number of moles of sodium nitrate in the solution.

Given:
- Mass of sodium nitrate = 19.0 g
- Molar mass of NaNO3 = 85.0 g/mol

Number of moles of NaNO3 = mass / molar mass
Number of moles = 19.0 g / 85.0 g/mol
Number of moles = 0.2235 mol

Next, we need to calculate the volume of the solution in liters:
Volume = 150. ml = 0.150 L

Now, we can calculate the concentration of the solution in mol/L:
Concentration = moles / volume
Concentration = 0.2235 mol / 0.150 L
Concentration = 1.49 mol/L

Therefore, the concentration of the chemist's sodium nitrate solution is 1.49 mol/L.