We know that the distance traveled by each wheel is the same when they rotate without slipping.
Let the number of turns made by the small wheel be x.
The distance traveled by the small wheel = circumference of small wheel * x
= 2πr1 * x, where r1 is the radius of the small wheel
The distance traveled by the large wheel = circumference of large wheel * 60 degrees
= 2πr2 * (60/360), where r2 is the radius of the large wheel
Since the distance traveled by both wheels is the same,
2πr1 * x = 2πr2 * (60/360)
x = r2 * (60/360) / r1
x = r2/r1 * 1/6
x = 200mm / 20mm * 1/6
x = 10 * 1/6
x = 5/3
Therefore, the small wheel makes 5/3 turns when the large wheel rotates through 60 degrees.
Two friction wheels are.of 20mm and 200mm respectively. They touch each other day o and rotate without slipping. Calculate the number of turns made by the small wheel when the large wheel rotates through 60degree
1 answer