Asked by Alisa

A golden wedding ring is 20mm in diameter and has a 14mm hole in the middle
A. What is the area of the ring
B. What is the cost of the ring if 1mmsquare of gold is equivalent to 5gh
Answered by PsyDAG
Area = pi r^2 r = d/2

A. pi (10^2 - 7^2) = ?

B. Need volume rather than area. What is the thickness of the ring?
Answered by oobleck
B. Assuming standardized ring pricing, as indicated by the price of 5gh/mm^2, then the cost is 5*(A) from above
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