An automobile starts from rest and accelerates to a final velocity in two stages along a straight road. Each stage occupies the same amount of time. In stage 1, the magnitude of the car's acceleration is 2.7 m/s2. The magnitude of the car's velocity at the end of stage 2 is 2.8 times greater than it is at the end of stage 1. Find the magnitude of the acceleration in stage 2.

2 answers

time for each stage = T
V1 = 2.7 T
V2 = 2.7 T + a T

2.7 T + a T = 2.8 (2.7 T)
2.7 + a = 2.8 * 2.7
a = 1.8*2.7
7.56