Question
A plane flies 200km on a bearing 032° it then flies 350km on a bearing 275°
Find the bearing and distance of the plane from it's starting point
Find the bearing and distance of the plane from it's starting point
Answers
GPT 3.5
To find the distance and bearing of the plane from its starting point, we will use the Law of Sines and trigonometry.
First, we can break down the two displacements of the plane into their horizontal and vertical components:
For the first leg:
Horizontal component: 200km * cos(032°) = 200km * 0.8387 = 167.74km
Vertical component: 200km * sin(032°) = 200km * 0.5446 = 108.92km
For the second leg:
Horizontal component: 350km * cos(275°) = 350km * -0.9659 = -337.06km
Vertical component: 350km * sin(275°) = 350km * -0.2588 = -90.34km
Next, we can find the total horizontal and vertical displacements of the plane:
Total horizontal displacement = 167.74km - 337.06km = -169.32km
Total vertical displacement = 108.92km - 90.34km = 18.58km
Now, we can use trigonometry to find the distance of the plane from its starting point:
Distance = √((-169.32)^2 + 18.58^2) ≈ 171.3km
Lastly, we can find the bearing of the plane from its starting point:
Bearing = arctan(18.58 / -169.32) ≈ -6.26°
Therefore, the plane is approximately 171.3km away from its starting point on a bearing of 006°.
First, we can break down the two displacements of the plane into their horizontal and vertical components:
For the first leg:
Horizontal component: 200km * cos(032°) = 200km * 0.8387 = 167.74km
Vertical component: 200km * sin(032°) = 200km * 0.5446 = 108.92km
For the second leg:
Horizontal component: 350km * cos(275°) = 350km * -0.9659 = -337.06km
Vertical component: 350km * sin(275°) = 350km * -0.2588 = -90.34km
Next, we can find the total horizontal and vertical displacements of the plane:
Total horizontal displacement = 167.74km - 337.06km = -169.32km
Total vertical displacement = 108.92km - 90.34km = 18.58km
Now, we can use trigonometry to find the distance of the plane from its starting point:
Distance = √((-169.32)^2 + 18.58^2) ≈ 171.3km
Lastly, we can find the bearing of the plane from its starting point:
Bearing = arctan(18.58 / -169.32) ≈ -6.26°
Therefore, the plane is approximately 171.3km away from its starting point on a bearing of 006°.
since bearings are measured clockwise from vertical, you have, for a distance d on a heading of θ,
horizontal component = d sinθ
vertical component = d cosθ
horizontal component = d sinθ
vertical component = d cosθ
GPT 3.5
My apologies for the mistake in the previous calculation. Let's correct it using the correct horizontal and vertical components as per your clarification.
For the first leg:
Horizontal component: 200km * sin(032°) = 200km * 0.5299 = 105.98km
Vertical component: 200km * cos(032°) = 200km * 0.8479 = 169.58km
For the second leg:
Horizontal component: 350km * sin(275°) = 350km * -0.7832 = -274.62km
Vertical component: 350km * cos(275°) = 350km * 0.6216 = 217.56km
Now, we can find the total horizontal and vertical displacements of the plane:
Total horizontal displacement = 105.98km - 274.62km = -168.64km
Total vertical displacement = 169.58km + 217.56km = 387.14km
Now, we can use trigonometry to find the distance of the plane from its starting point:
Distance = √((-168.64)^2 + 387.14^2) ≈ 423.67km
Lastly, we can find the bearing of the plane from its starting point:
Bearing = arctan(168.64 / 387.14) ≈ 22.01°
Therefore, the plane is approximately 423.67km away from its starting point on a bearing of 022°.
For the first leg:
Horizontal component: 200km * sin(032°) = 200km * 0.5299 = 105.98km
Vertical component: 200km * cos(032°) = 200km * 0.8479 = 169.58km
For the second leg:
Horizontal component: 350km * sin(275°) = 350km * -0.7832 = -274.62km
Vertical component: 350km * cos(275°) = 350km * 0.6216 = 217.56km
Now, we can find the total horizontal and vertical displacements of the plane:
Total horizontal displacement = 105.98km - 274.62km = -168.64km
Total vertical displacement = 169.58km + 217.56km = 387.14km
Now, we can use trigonometry to find the distance of the plane from its starting point:
Distance = √((-168.64)^2 + 387.14^2) ≈ 423.67km
Lastly, we can find the bearing of the plane from its starting point:
Bearing = arctan(168.64 / 387.14) ≈ 22.01°
Therefore, the plane is approximately 423.67km away from its starting point on a bearing of 022°.
Related Questions
Calculate the lenght of the return journey from point c to point a when an aircraft flies from its b...
a plane starts from a point P and flies 240km on a bearing of 120degrees to Q. At Q the plane makes...
An aero plane flies from a town X on a bearing of N45°E to another town Y, a distance of 200km. it t...
A plane flies from A and B,a distance of.a 120km on a bearing of 035°. If then changes direction and...