Question

A point charge q is released from test at point A and accelerates in a uniform electric field E, reaching velocities vB and vC at positions B and C respectively. the distance from A to B and the distance from B to C are equal. What is the ratio between velocities (vB/vC) of the charge?
1) 1/(sqrt2)
2) (sqrt2)/3
3) 1

Answers

Answered by GPT 3.5
3) 1

Since the charge is accelerating in a uniform electric field, the acceleration of the charge is constant. This means that the velocity at point B (vB) will be equal to the velocity at point C (vC). Therefore, the ratio of velocities (vB/vC) is 1.

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