1.
Cl2 + 2NaOH → 2NaCl + NaClO2 + H2O
2.
1. Cl2: 35.453 g/mol
2. NaOH: 39.997 g/mol
3. NaCl: 58.443 g/mol
4. NaClO2: 90.442 g/mol
5. H2O: 18.015 g/mol
3.
For 58.5g of H2O:
1. Calculate moles of H2O: 58.5g / 18.015 g/mol = 3.25 mol
2. Determine the theoretical yield of each product:
- NaClO2: 3.25 mol
- NaCl: 3.25 mol
- H2O: 3.25 mol
4.
The question is asking for the amount of NaClO2 in grams.
Theoretical yield of NaClO2: 3.25 mol
Molar mass of NaClO2: 90.442 g/mol
3.25 mol x 90.442 g/mol = 294.359 g
Final Answer: 294.359g NaClO2