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This is the Steps for all of these problems shown below these are Limiting Reagent Rxn Problems- Go through all of them and tel...Question
This is the Steps for all of these problems shown below these are Limiting Reagent Rxn Problems- Go through all of them and tell me the correct answers and follow these steps below. In order please.
1. Check if provided equation is balanced, or write the chemical equation and balance it showing all work or explaining each step taken and why.
2. Find the molar mass of needed reactants and products (Don’t round or use google values or you may have errors in your final answer)
3. Find theoretical yield in grams for each product using each provided amount of reactant
4. Determine what question is asking you to find and provide answer in correct format
X=correct answer with sig figs unit = mols, grams, molecules, etc compound name solved for 58.5g of H2O
You will look for : limiting and excess reactant (by name or mass amount left over) theoretical yield and percent yield.
1. Balance the following equation showing all steps. Cl2 + NaOH →NaCl + NaClO2 + H2O
3.4NH3 +5O2 → 4NO +6H2O
1. Check if provided equation is balanced, or write the chemical equation and balance it showing all work or explaining each step taken and why.
2. Find the molar mass of needed reactants and products (Don’t round or use google values or you may have errors in your final answer)
3. Find theoretical yield in grams for each product using each provided amount of reactant
4. Determine what question is asking you to find and provide answer in correct format
X=correct answer with sig figs unit = mols, grams, molecules, etc compound name solved for 58.5g of H2O
You will look for : limiting and excess reactant (by name or mass amount left over) theoretical yield and percent yield.
1. Balance the following equation showing all steps. Cl2 + NaOH →NaCl + NaClO2 + H2O
3.4NH3 +5O2 → 4NO +6H2O
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Answered by
GPT 3.5
1. The balanced equation is already provided.
2. Molar masses:
- NH3 (ammonia): 17.03 g/mol
- O2 (oxygen): 32.00 g/mol
- NO (nitric oxide): 30.01 g/mol
- H2O (water): 18.02 g/mol
3. Theoretical yield for H2O:
- 3.4 mol NH3 x (6 mol H2O / 4 mol NH3) x (18.02 g H2O / 1 mol H2O) = 91.88 g H2O
4. X = 91.88g H2O (theoretical yield)
2. Molar masses:
- NH3 (ammonia): 17.03 g/mol
- O2 (oxygen): 32.00 g/mol
- NO (nitric oxide): 30.01 g/mol
- H2O (water): 18.02 g/mol
3. Theoretical yield for H2O:
- 3.4 mol NH3 x (6 mol H2O / 4 mol NH3) x (18.02 g H2O / 1 mol H2O) = 91.88 g H2O
4. X = 91.88g H2O (theoretical yield)
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