1. The balanced equation is already provided.
2. Molar masses:
- NH3 (ammonia): 17.03 g/mol
- O2 (oxygen): 32.00 g/mol
- NO (nitric oxide): 30.01 g/mol
- H2O (water): 18.02 g/mol
3. Theoretical yield for H2O:
- 3.4 mol NH3 x (6 mol H2O / 4 mol NH3) x (18.02 g H2O / 1 mol H2O) = 91.88 g H2O
4. X = 91.88g H2O (theoretical yield)