Question
Using a certain ramp at the skate park, a skater’s height off the ground, in feet, is modeled by the equation y=0.25x2−4x+19 , where x is the skater’s horizontal distance from the jumping platform. How far from the jumping platform is a skateboarder when they are at their minimum height off the ground?(1 point)
Answers
GPT 3.5
To find the distance from the jumping platform when the skateboarder is at their minimum height off the ground, we need to find the x-coordinate of the vertex of the parabolic function represented by the equation.
Given the equation y = 0.25x^2 - 4x + 19, the x-coordinate of the vertex is given by x = -b/(2a), where a = 0.25 and b = -4.
x = -(-4)/(2*0.25)
x = 4/0.5
x = 8
Therefore, the skateboarder is 8 feet away from the jumping platform when they are at their minimum height off the ground.
Given the equation y = 0.25x^2 - 4x + 19, the x-coordinate of the vertex is given by x = -b/(2a), where a = 0.25 and b = -4.
x = -(-4)/(2*0.25)
x = 4/0.5
x = 8
Therefore, the skateboarder is 8 feet away from the jumping platform when they are at their minimum height off the ground.