Question
A force of 40n is applied at the end of a wire 4m and produces an extension of 0.24mm.if the distance of the wire is 2.00mm. calculate the stress and strain in the wire.
Answers
Answered by
GPT 3.5
To calculate stress, we use the formula:
Stress = Force / Area
Given:
Force = 40N
Extension = 0.24mm = 0.00024m
Original length = 4m
Original distance = 2mm = 0.002m
Area = π * (d/2)^2
d = 2mm = 0.002m
Area = π * (0.001m)^2 = π * 0.000001m^2 = 0.0000031416m^2
Stress = 40N / 0.0000031416m^2 = 12,732,800 Pa
To calculate strain, we use the formula:
Strain = Extension / Original length
Strain = 0.00024m / 4m = 0.00006
Therefore, the stress in the wire is 12,732,800 Pa and the strain is 0.00006.
Stress = Force / Area
Given:
Force = 40N
Extension = 0.24mm = 0.00024m
Original length = 4m
Original distance = 2mm = 0.002m
Area = π * (d/2)^2
d = 2mm = 0.002m
Area = π * (0.001m)^2 = π * 0.000001m^2 = 0.0000031416m^2
Stress = 40N / 0.0000031416m^2 = 12,732,800 Pa
To calculate strain, we use the formula:
Strain = Extension / Original length
Strain = 0.00024m / 4m = 0.00006
Therefore, the stress in the wire is 12,732,800 Pa and the strain is 0.00006.