Asked by Yterry
A force of 6.2 N applied to the spiral spring of length 9.2 cm causes it to extend by 0.034 m. What is the length of the spiral spring when a force of 4.6 N is applied to it provided the elastic limit is not exceeded?
Answers
Answered by
oobleck
If just a force of 4.6N, then it extends
4.6/6.2 * 0.034 = ____ cm
If you mean an additional 4.6N, then it extends an additional
(6.2+4.6)/6.2 = ____ cm
Now just add those to the original 9.2 cm length
4.6/6.2 * 0.034 = ____ cm
If you mean an additional 4.6N, then it extends an additional
(6.2+4.6)/6.2 = ____ cm
Now just add those to the original 9.2 cm length
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