Asked by maria
prove the following integrals:
a)sin3xcos7xdx = -1/20cos(10x)+1/8cos(4x)
b)sin8xcos3xdx = -1/22cos(11x)-1/10cos(5x)
a)sin3xcos7xdx = -1/20cos(10x)+1/8cos(4x)
b)sin8xcos3xdx = -1/22cos(11x)-1/10cos(5x)
Answers
Answered by
bobpursley
In the first, cos7x= cos(4x+3x) then you have an identity to reduce that .
In the second, change sin8x to sin(5x+3x) to its identity.
In the second, change sin8x to sin(5x+3x) to its identity.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.