Try differentiate
sqrt(x)
and see if what you get inspires you.
I need help with integrals and I need help with the problem.
Integral of 4/sqrt(x)dx
4 answers
Integral of 4/sqrt(x)dx=
(x)^(-1/2)dx=(x)^(-1/2)dx
Integral of 4/sqrt(x)dx=4*Integral of
(x)^(-1/2)dx
Integral of x^n dx= x^(n+1) / (n+1)
Integral of (x)^(-1/2)dx=x^(-1/2+1) / (-1/2+1)= x^(1/2) / (1/2)= 2*sqrt(x)
Integral of 4/sqrt(x)dx=4*2*sqrt(x)+C= 8*sqroot(x)+C
(x)^(-1/2)dx=(x)^(-1/2)dx
Integral of 4/sqrt(x)dx=4*Integral of
(x)^(-1/2)dx
Integral of x^n dx= x^(n+1) / (n+1)
Integral of (x)^(-1/2)dx=x^(-1/2+1) / (-1/2+1)= x^(1/2) / (1/2)= 2*sqrt(x)
Integral of 4/sqrt(x)dx=4*2*sqrt(x)+C= 8*sqroot(x)+C
i know that the derivative of that is 1/2x^(-1/2) i still don't know what to do
oh wow thank you so much!! that makes sense!!
2 answers