Question
Write equilibrium Constant expressions (k) for the following reactions:
Ni(s)+ 4CO(g) <-> Ni(CO)₄
HF(aq) <-> H(aq) + F(aq)
Cl₂(g)+2Br(aq) <-> Br₂(l) + 2Cl(aq)
Ni(s)+ 4CO(g) <-> Ni(CO)₄
HF(aq) <-> H(aq) + F(aq)
Cl₂(g)+2Br(aq) <-> Br₂(l) + 2Cl(aq)
Answers
DrBob222
What do you not understand about how to write these expressions? It's just "follow the rules."
Aidan
when the element have different states, ie. (aq) (s) (g) etc. doesn't that change the way you write the constant expressions?
DrBob222
Yes. As a general rule, solids and pure liquids don't show up in the expression.
Ni(s)+ 4CO(g) <-> Ni(CO)₄
HF(aq) <-> H(aq) + F(aq)
Cl₂(g)+2Br(aq) <-> Br₂(l) + 2Cl(aq)
So #2 is
K=(H^+)(F^-)/(HF) and the concn of each is determined by the molarity.
For #1, K = (CO)^4
Ni(s)+ 4CO(g) <-> Ni(CO)₄
HF(aq) <-> H(aq) + F(aq)
Cl₂(g)+2Br(aq) <-> Br₂(l) + 2Cl(aq)
So #2 is
K=(H^+)(F^-)/(HF) and the concn of each is determined by the molarity.
For #1, K = (CO)^4