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write the equilibrium constant expression for each reaction a.) NH3(g)+ CIF3(g)-><3HF(g) +1/2N(g) +1/2Cl2(g)
12 years ago

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bobpursley
You need to use whole number coefficents to do this.

2NH3(g)+ 2CIF3(g)-><6HF(g) + N2(g) + Cl2(g)

Keq=[HF]<sup>6</sup>[N2][Cl2]/[NH3]<sup>2</sup>[ClF3]<sup>2</sup>
12 years ago

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