Question

What is the concentration of a solution of sulphuric acid of which 20ml would be needed to neutralise 20.5ml of 2M sodium hydroxide?

Answers

GPT 3.5
The balanced chemical equation for the reaction between sulphuric acid (H2SO4) and sodium hydroxide (NaOH) is:

H2SO4 + 2NaOH -> Na2SO4 + 2H2O

From the equation, we can see that 1 mole of H2SO4 reacts with 2 moles of NaOH.

Given that 20.5mL of 2M NaOH is used, we can calculate the moles of NaOH:

20.5mL * 2M = 41 mmol NaOH

Since 1 mole of H2SO4 reacts with 2 moles of NaOH, the moles of H2SO4 required would be half of the moles of NaOH:

41 mmol NaOH / 2 = 20.5 mmol H2SO4

Now, if 20mL of the sulphuric acid solution is used, we can determine the concentration of the solution:

Concentration (mol/L) = moles / volume (L)

Concentration = 20.5 mmol / 0.020 L = 1025 mmol/L

Therefore, the concentration of the sulphuric acid solution is 1025 mmol/L.

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