Question
What is the concentration of a solution of sulphuric acid of which 20ml would be needed to neutralise 20.5ml of 2M sodium hydroxide?
Answers
GPT 3.5
The balanced chemical equation for the reaction between sulphuric acid (H2SO4) and sodium hydroxide (NaOH) is:
H2SO4 + 2NaOH -> Na2SO4 + 2H2O
From the equation, we can see that 1 mole of H2SO4 reacts with 2 moles of NaOH.
Given that 20.5mL of 2M NaOH is used, we can calculate the moles of NaOH:
20.5mL * 2M = 41 mmol NaOH
Since 1 mole of H2SO4 reacts with 2 moles of NaOH, the moles of H2SO4 required would be half of the moles of NaOH:
41 mmol NaOH / 2 = 20.5 mmol H2SO4
Now, if 20mL of the sulphuric acid solution is used, we can determine the concentration of the solution:
Concentration (mol/L) = moles / volume (L)
Concentration = 20.5 mmol / 0.020 L = 1025 mmol/L
Therefore, the concentration of the sulphuric acid solution is 1025 mmol/L.
H2SO4 + 2NaOH -> Na2SO4 + 2H2O
From the equation, we can see that 1 mole of H2SO4 reacts with 2 moles of NaOH.
Given that 20.5mL of 2M NaOH is used, we can calculate the moles of NaOH:
20.5mL * 2M = 41 mmol NaOH
Since 1 mole of H2SO4 reacts with 2 moles of NaOH, the moles of H2SO4 required would be half of the moles of NaOH:
41 mmol NaOH / 2 = 20.5 mmol H2SO4
Now, if 20mL of the sulphuric acid solution is used, we can determine the concentration of the solution:
Concentration (mol/L) = moles / volume (L)
Concentration = 20.5 mmol / 0.020 L = 1025 mmol/L
Therefore, the concentration of the sulphuric acid solution is 1025 mmol/L.
Related Questions
A 20ml of a 1M KOH solution is used to react with sulphuric acid, what is the number of mols of KOH...
concentrated aqueous sulphuric acid is 98% sulphuric acid by mass and has a density of 1.80 g/l. Vol...
Suppose you need 2.0 L of 6.0 M sulphuric acid, and you have a bottle of concentrated acid of 18.0 M...
20.0cm3of a solution containing 4g/L of sodium hydroxide was neutralize by 8cm of dilute sulphuric a...