To find the distance from the player at which the ball reaches its maximum height, we need to determine the x-coordinate of the vertex of the parabolic equation representing the trajectory of the ball.
The vertex of a parabola given in the form y = ax^2 + bx + c is located at the x-coordinate x = -b/(2a).
In this case, the equation for the trajectory of the ball is y = -0.05x^2 + 0.8x + 6.
Comparing this with the standard form of a quadratic equation y = ax^2 + bx + c, we have a = -0.05 and b = 0.8.
Therefore, the x-coordinate of the vertex is x = -0.8 / (2 * -0.05) = -0.8 / (-0.1) = 8.
So, the ball reaches its maximum height at a distance of 8 feet from the player.
You and your grandfather attend a live NBA game. One of the players is getting ready to make a free throw. The equation y=−0.05x2+0.8x+6
represents the trajectory of the ball from when it leaves the player’s hands. The player is 6 feet tall. At what distance from the player does the ball reach its maximum height
1 answer
1 answer