You and your grandfather attend a live NBA game. One of the players is getting ready to make a free throw. The equation y=βˆ’0.05x2+0.8x+6

𝑦
=
βˆ’
0.05
π‘₯
2
+
0.8
π‘₯
+
6
represents the trajectory of the ball from when it leaves the player’s hands. The player is 6 feet tall. At what distance from the player does the ball reach its maximum height?

1 answer

To find the distance from the player at which the ball reaches its maximum height, we need to determine the vertex of the parabolic equation given by:

\[ y = -0.05x^2 + 0.8x + 6 \]

The x-coordinate of the vertex of a parabola described by the equation \(y = ax^2 + bx + c\) can be calculated using the formula:

\[ x = -\frac{b}{2a} \]

In this case, \(a = -0.05\) and \(b = 0.8\). Plugging these values into the formula gives:

\[ x = -\frac{0.8}{2 \cdot -0.05} = -\frac{0.8}{-0.1} = 8 \]

Thus, the ball reaches its maximum height at a distance of \(8\) feet from the player.