Question

I posted this problem the other day and someone answered it but when I checked my book I realized that I wrote the problem wrong. This morning when I posted I had put the wrong answer. The answer is suppose to be 1/8 but I don't understand how to solve the problem. Help would be greatly appreciated.


(1/4)^2/(1/2-3/4)+ 3/2^3 (It's all one equation)

Answer 1

First of all, it is not an equation, since it does not have an equal sign. Second, I think you wanted the sequence to be like this, so it is not just the 2 that is cubed:

(1/4)^2/(1/2-3/4)+ (3/2)^3

(3/2)^3 = 3/2 * 3/2 * 3/2 = 27/8

(1/4)^2 = 1/4 * 1/4 = 1/16

1/2 - 3/4 = -1/4

(1/16)/(-1/4) = (1/16) * -4 = -4/16 = -1/4 = -2/8

-2/8 + 27/8 = 25/8 = 3 1/8

I hope this breaks it down well enough for you to understand.