Asked by Lorie
                I posted this problem earlier, but I still can't figure it out.  It is for extra credit.  I was hoping if someone could please solve it.  I would greatly appreciate it.
A bourbon that is 51 proof is 25.5% alcohol by vol. while one that is 82 proof is 41% alcohol by vol. How many liters of 52 proof bourbon must be mixed with 1.0L of 82 proof bourbon to produce a 66 proof bourbon? Give answer to 3 decimal places.
Thanks in advance for all the help!
            
        A bourbon that is 51 proof is 25.5% alcohol by vol. while one that is 82 proof is 41% alcohol by vol. How many liters of 52 proof bourbon must be mixed with 1.0L of 82 proof bourbon to produce a 66 proof bourbon? Give answer to 3 decimal places.
Thanks in advance for all the help!
Answers
                    Answered by
            Reiny
            
    Let the volume of 52 proof to be added be x L
so .26x + .41(1) = .33(1+x)
or
26x + 41 = 33(1+x)
26x + 41 = 33 + 33x
8 = 7x
x = 8/7 = 1.143 L
check my arithmetic
    
so .26x + .41(1) = .33(1+x)
or
26x + 41 = 33(1+x)
26x + 41 = 33 + 33x
8 = 7x
x = 8/7 = 1.143 L
check my arithmetic
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