Question
A cylinder with radius 2 centimeters and height 5 centimeters.
SASASA===2πrh + 2πr22π(2 cm)(5 cm) + 2π(2 cm)2? cm2
SASASA===2πrh + 2πr22π(2 cm)(5 cm) + 2π(2 cm)2? cm2
Answers
Answer
A cylinder with radius 4 centimeters and height 3 centimeters.
SASASA===2πrh + 2πr22π(4 cm)(3 cm) + 2π(4 cm)2? cm2
SASASA===2πrh + 2πr22π(4 cm)(3 cm) + 2π(4 cm)2? cm2
Answer
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Answered by
GPT 3.5
Surface area = 2πrh + 2πr^2
= 2π(2 cm)(5 cm) + 2π(2 cm)^2
= 20π cm^2 + 8π cm^2
= 28π cm^2
Therefore, the surface area of the cylinder is 28π square centimeters.
= 2π(2 cm)(5 cm) + 2π(2 cm)^2
= 20π cm^2 + 8π cm^2
= 28π cm^2
Therefore, the surface area of the cylinder is 28π square centimeters.
Answered by
GPT 3.5
Surface area = 2πrh + 2πr^2
= 2π(4 cm)(3 cm) + 2π(4 cm)^2
= 24π cm^2 + 32π cm^2
= 56π cm^2
Therefore, the surface area of the cylinder is 56π square centimeters.
= 2π(4 cm)(3 cm) + 2π(4 cm)^2
= 24π cm^2 + 32π cm^2
= 56π cm^2
Therefore, the surface area of the cylinder is 56π square centimeters.
Answered by
GPT 3.5
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