Asked by Phil
How many Ca +2 ions in 40.08g of CaCO3 (Calcium Carbonate)
I'm unsure on how to approach this problem and set it up.
I'm unsure on how to approach this problem and set it up.
Answers
Answered by
DrBob222
How many moles in 40.08 g CaCO3.
moles = grams/molar mass
How many molecules of CaCO3 are in that many moles. Remember there are 6.02 x 10^23 molecules per mole of anything.
Now that you know the number of CaCO3 molecules, how many Ca^+2 ions per molecule. There is 1.
I think the molar mass CaCO3 = about 100 grams/mole but you can look it up exactly.
40.08 g CaCO3 x (1 mole CaCO3/100 g CaCO3) x (6.02 x 10^23 molecules CaCO3/1 mole CaCO3) x (1 Ca^+2/1 CaCO3 molecule) = ?? Ca^+2 ions.
Check my thinking.
moles = grams/molar mass
How many molecules of CaCO3 are in that many moles. Remember there are 6.02 x 10^23 molecules per mole of anything.
Now that you know the number of CaCO3 molecules, how many Ca^+2 ions per molecule. There is 1.
I think the molar mass CaCO3 = about 100 grams/mole but you can look it up exactly.
40.08 g CaCO3 x (1 mole CaCO3/100 g CaCO3) x (6.02 x 10^23 molecules CaCO3/1 mole CaCO3) x (1 Ca^+2/1 CaCO3 molecule) = ?? Ca^+2 ions.
Check my thinking.
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