Question
a student mixed a 50.0mL of water containing 0.50 mols of HCl at 22.5 degC with 50.0 mL of water containing 0.50 mol NaOH at 22.5 degC in a foam cup calorimeter.the temp increases to 26.0 degC. how much heat in kJ was released by the reaction? please show how you found the answer so i can understand how you did it.
Answers
how many moles are present in 56.2L of NE(g)?
q = mass x specific heat x delta T.
mass = 100 g (I assume we assume the density of the solution is 1.00 g/mL).
specific heat = 4.184 J/g*C
delta T = 26.0 - 22.5 = ??
q will be in Joules and you will need to convert to kJ.
mass = 100 g (I assume we assume the density of the solution is 1.00 g/mL).
specific heat = 4.184 J/g*C
delta T = 26.0 - 22.5 = ??
q will be in Joules and you will need to convert to kJ.
You should not piggy back on another question. Often these questions get overlooked.
moles = grams/molar mass.
By the way, there is no such thing as NE. I assume you meant Ne.
moles = grams/molar mass.
By the way, there is no such thing as NE. I assume you meant Ne.
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