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A student mixed 40ml of 0.2m Na2co3 solution with 50 ml f 0.25M cacl2 solution , what is the except number of moles of naclkkw that I will be formed ?

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Na2CO3 + CaCl2 ==> CaCO3 + 2NaCl

millimols Na2CO3 = mL x M = estimated 8
mmols CaCl2 = estimated 12.5
So you will form 8 mmols (0.008 mols) CaCO3.

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