The position of an object changes with time according to the expression x(t) = 5t62 = 3t - 1. What is the position of the object when its velocity is 11 m/s?
2 answers
Take the derivative of x(t) with respect to t to find a function v(t). Set that equal to 11, solve for t, then put that in to x(t) and compute x.
Do you mean x(t) = 5t^2 +3t -1?
What you wrote makes no sense.
If you meant what I wrote, the velocity at time t is
V = x'(t) = 10 t + 3
When x'(t) = 11,
11 = 10 t + 3
10 t = 8
t = 0.8
use x(t) to compute x at that time
What you wrote makes no sense.
If you meant what I wrote, the velocity at time t is
V = x'(t) = 10 t + 3
When x'(t) = 11,
11 = 10 t + 3
10 t = 8
t = 0.8
use x(t) to compute x at that time
0 answers