Question
The position of an object as a function of time is r⃗ =(3.2t+ 1.8 t2)i^+(1.7t− 2.4 t2)j^m, where t is the time in seconds.
Find the object’s magnitude of the acceleration.
What is the direction of the acceleration?
Find the object’s magnitude of the acceleration.
What is the direction of the acceleration?
Answers
Damon
Oh all right I will do one more before getting grandkids up for school.
dr/dt = (3.2+3.6t)i + (1.7-4.8t)j
d^2r/dt^2 = 3.6 i - 4.8 j
which is the acceleration, so what else is new?
|a| = sqrt(3.6^2 + 4.8^2)
tan angle north of east = -4.8/3.6
so angle South of East = 53.1 deg
dr/dt = (3.2+3.6t)i + (1.7-4.8t)j
d^2r/dt^2 = 3.6 i - 4.8 j
which is the acceleration, so what else is new?
|a| = sqrt(3.6^2 + 4.8^2)
tan angle north of east = -4.8/3.6
so angle South of East = 53.1 deg