x^2 + 7x + 10 = 0
Using the quadratic formula:
x = [-b ± √(b^2 - 4ac)] / 2a
Here, a = 1, b = 7, and c = 10
x = [-7 ± √(7^2 - 4*1*10)] / 2(1)
x = [-7 ± √(49 - 40)] / 2
x = [-7 ± √9] / 2
x = [-7 ± 3] / 2
This gives two possible values for x when solving for the positive and negative square roots:
x = (-7 + 3) / 2 = -2
x = (-7 - 3) / 2 = -5
Therefore, x = -2 and x = -5 are the solutions to the equation.
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
x2 + 10 = –7x
(1 point)
Responses
x = 2, 5
x = 2, 5
x = –2, 5
x = –2, 5
x = 2, –5
x = 2, –5
x = –2, –5
1 answer