Using the quadratic formula, we can find the solutions to the equation 3x^2 + 18x + 24 = 0.
The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a = 3, b = 18, and c = 24.
Plugging in the values, we get:
x = (-18 ± √(18^2 - 4 * 3 * 24)) / (2 * 3)
Simplifying further, we have:
x = (-18 ± √(324 - 288)) / 6
x = (-18 ± √36) / 6
Taking the square root, we have:
x = (-18 ± 6) / 6
Simplifying the expression, we get:
x = (-18 + 6) / 6 = -12 / 6 = -2
x = (-18 - 6) / 6 = -24 / 6 = -4
Therefore, the solutions to the equation 3x^2 + 18x + 24 = 0 are x = -2 and x = -4.
Using the quadratic formula, find the solution to 3x2+18x+24=0
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(1 point)
Responses
x = - 2
x = - 2
x = -2, x = -4
x = -2, x = -4
x = - 4
x = - 4
x = 4, x = 2
1 answer