What is the volume of a shoebox that is 112 ft. long, 34 ft. wide, and 12 ft. tall? Apply the V=B×h formula to solve.(1 point)

Responses

118 ft.3
1 Start Fraction 1 over 8 end fraction ft cubed

34 ft.3
Start Fraction 3 over 4 end fraction ft cubed

916 ft.3
Start Fraction 9 over 16 end fraction ft cubed

234 ft.3

3 answers

The volume of a shoebox is calculated by multiplying the area of the base (length x width) by the height.

V = B x h

Given that the shoebox is 112 ft. long, 34 ft. wide, and 12 ft. tall:

V = (112 ft. x 34 ft.) x 12 ft.
V = 3808 ft. x 12 ft.
V = 45696 ft³

Therefore, the volume of the shoebox is 45696 ft³.
those arent the options these are

118 ft.3
1 Start Fraction 1 over 8 end fraction ft cubed

34 ft.3
Start Fraction 3 over 4 end fraction ft cubed

916 ft.3
Start Fraction 9 over 16 end fraction ft cubed

234 ft.3
Apologies for the oversight. Let's solve this using the options provided:

The volume of the shoebox is given by V = B x h, where B is the area of the base (length x width) and h is the height.

Given:
Length = 112 ft
Width = 34 ft
Height = 12 ft

Volume = 112 ft * 34 ft * 12 ft
Volume = 45408 ft³

From the options provided, the closest matching volume is 916 ft³.

Therefore, the correct answer is:
916 ft.³