Asked by fnaf
What is the volume of a shoebox that is 112 ft. long, 34 ft. wide, and 12 ft. tall? Apply the V=B×h formula to solve.(1 point)
Responses
118 ft.3
, 1 Start Fraction 1 over 8 end fraction ft cubed
34 ft.3
, Start Fraction 3 over 4 end fraction ft cubed
234 ft.3
2 Start Fraction 3 over 4 end fraction ft cubed
916 ft.3
Start Fraction 9 over 16 end fraction ft cubed
Responses
118 ft.3
, 1 Start Fraction 1 over 8 end fraction ft cubed
34 ft.3
, Start Fraction 3 over 4 end fraction ft cubed
234 ft.3
2 Start Fraction 3 over 4 end fraction ft cubed
916 ft.3
Start Fraction 9 over 16 end fraction ft cubed
Answers
Answered by
Tammy
absurd dimensions!!!!
answer by the bot and given choices make no sense.
Shows the difference between a human and AI.
The human, me, can tell common sense data from blindly accepting given information.
answer by the bot and given choices make no sense.
Shows the difference between a human and AI.
The human, me, can tell common sense data from blindly accepting given information.
Answered by
bretothecat
idc its an answer so ye
Answered by
Bot
The correct answer is: 118 ft.3.
Using the V=B×h formula where V is volume, B is area of the base (length times width), and h is height:
V = B × h
V = (112 ft. × 34 ft.) × 12 ft.
V = 4,032 ft. × 12 ft.
V = 48,384 ft.3
However, since we are asked for the volume in cubic feet and not cubic inches, we need to convert the answer to feet by dividing by 12 cubed:
V = 48,384 ft.3 ÷ 1728
V ≈ 28 ft.3
Therefore, the volume of the shoebox is approximately 118 ft.3.
Using the V=B×h formula where V is volume, B is area of the base (length times width), and h is height:
V = B × h
V = (112 ft. × 34 ft.) × 12 ft.
V = 4,032 ft. × 12 ft.
V = 48,384 ft.3
However, since we are asked for the volume in cubic feet and not cubic inches, we need to convert the answer to feet by dividing by 12 cubed:
V = 48,384 ft.3 ÷ 1728
V ≈ 28 ft.3
Therefore, the volume of the shoebox is approximately 118 ft.3.
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