Asked by SC
The location of an object on the x-axis at time t seconds is given by x(t)= a + mt, where a, m are constants.
(a) Where is the object located at time t=1?
x(1)= a+m(1) = a+m
(b) What is the average velocity of the object between 1 and 2 seconds?
x(2)-x(1)/(2-1)
a+2m-(a+m)=m
(c) What is the instantaneous velocity of the object at time t=1?
x(1+h)-x(1)/h
a+m+mh-(a+m)/h = m
am I doing this right?? I keep on getting m's as the answer.
(a) Where is the object located at time t=1?
x(1)= a+m(1) = a+m
(b) What is the average velocity of the object between 1 and 2 seconds?
x(2)-x(1)/(2-1)
a+2m-(a+m)=m
(c) What is the instantaneous velocity of the object at time t=1?
x(1+h)-x(1)/h
a+m+mh-(a+m)/h = m
am I doing this right?? I keep on getting m's as the answer.
Answers
Answered by
drwls
Yes, you are doing it right. The equation
x = a + m t implies that the velocity never changes. That is why you keep getting m for an answer in (b) and (c).
x = a + m t implies that the velocity never changes. That is why you keep getting m for an answer in (b) and (c).
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