Question

A graph titled Position versus time for with horizontal axis time (seconds) and vertical axis position (meters). A straight blue line runs with an upward slope from 0 seconds 3 meters to 4 seconds 15 meters.
The starting position of this object is
m.

The object is traveling at a velocity of
m/s.

Answer 1

To analyze the information provided by the graph titled "Position versus Time":

1. **Starting position of the object**: The starting position corresponds to the position on the vertical axis when time is 0 seconds. According to your description, the graph shows that at 0 seconds, the position is at 3 meters. Therefore, the starting position of this object is **3 meters**.

2. **Velocity of the object**: The velocity can be calculated using the formula for slope in a graph, which is:
\[
\text{Velocity} = \frac{\text{Change in position}}{\text{Change in time}}.
\]
From 0 seconds to 4 seconds, the position changes from 3 meters to 15 meters. So the change in position (Δy) is:
\[
\Delta y = 15 \text{ m} - 3 \text{ m} = 12 \text{ m}.
\]
The change in time (Δx) is:
\[
\Delta x = 4 \text{ s} - 0 \text{ s} = 4 \text{ s}.
\]
Now, plug these into the velocity formula:
\[
\text{Velocity} = \frac{12 \text{ m}}{4 \text{ s}} = 3 \text{ m/s}.
\]

So, the answers are:
- The starting position of this object is **3 meters**.
- The object is traveling at a velocity of **3 m/s**.