7x + 5 = 4x + 5 + 3x
simplifies to
7x + 5 = 7x + 5
Which appears to then support any integer, so I think it's C.
to test:
7(*2) + 5 = 4(*2) + 5 + 3(*2)
14 + 5 = 8 + 5 + 6
19 = 19
to test:
7(*3) + 5 = 4(*3) + 5 + 3(*3)
21 + 5 = 12 + 5 + 9
26 = 26
and so on.
3.
Which of the following equations has an infinite number of solutions? (1 point)
3x – 3 = –4x
2y + 4 – y = 16
7x + 5 = 4x + 5 + 3x
6y – 2 = 2(y – 1)
I think it's A.
3 answers
Nope. x = 3/7
There will be one where the variable just disappears, leaving a true equation. For example, if you have something like
2x-4 = x-4+x
that is true no matter what value you pick for x.
There will be one where the variable just disappears, leaving a true equation. For example, if you have something like
2x-4 = x-4+x
that is true no matter what value you pick for x.
thank you guys! just in time.