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3 of 73 of 7 Items Question If the squared differences of the x-coordinates and y-coordinates are 64 and 36 respectively, what is the distance between the two points?(1 point) Responses 64 + 36−−−−−−−√ = 10 units 64 + 36−−−−−−−√ = 10 units 64 + 36−−−−−−−√ = 8 + 6 = 14 units 64 + 36−−−−−−−√ = 8 + 6 = 14 units 64 − 36−−−−−−−√ = 5.29 units 64 − 36−−−−−−−√ = 5.29 units 64 − 36−−−−−−−√ = 8− 6= 2 units 64 − 36−−−−−−−√ = 8− 6= 2 units Skip to navigation page 5 of 5

Answer 1

To find the distance between two points in a 2-dimensional space when you have the squared differences of the x-coordinates and y-coordinates, you can use the distance formula:

\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]

In your case, the squared differences are given as:

- Squared difference in x-coordinates: \( (x_2 - x_1)^2 = 64 \)
- Squared difference in y-coordinates: \( (y_2 - y_1)^2 = 36 \)

To find the distance, you substitute these values into the distance formula:

\[
d = \sqrt{64 + 36}
\]

Now calculate \(64 + 36\):

\[
64 + 36 = 100
\]

Now take the square root of 100:

\[
d = \sqrt{100} = 10 \text{ units}
\]

So the correct response is:

**64 + 36−−−−−−−√ = 10 units**.