Question

3. How much 0.10 M Base (in mL) is required to neutralize 8.00 mL of the 0.10 M acid?
Base Acid Base Volume (mL)
NaOH HCl ____________
NaOH HC2H3O2 _____________

4. How would the volume of base change from problem three if the 8.00 mL of 0.10 M Acid was first diluted with 100 mL of water (like it will be in the experiment you perform in lab)?


A. The volume would decrease.
B. No change.
C. The volume would increase.
D. Not enough information is given to predict what would happen.

Answer 1

i love pie

Answer 2

I need help with a chemistry problem. Here it is A quantity of gas has a volume of 14L at STP. What is the volume (in L) at 9.7 atm and 94 C? Can you help me set up the equation?

Answer 3

The base/acid problem was answered above.

Answer 4

PV = nRT. Don't forget to use temperature in Kelvin, which is Kelvin = 273 + C.

Answer 5

In the future, note that you probably can get help a little faster if you go to the top of the page, click on Ask a New Question, and post your own question instead of piggy-backing on another post.

Answer 6

actually nobody even bothered to answer it...i just see the same person giving an explanation that might not exactly be comprehended by others...