If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
6/15 * 4/15 * 5/15 = ?
Without replacement, there is one less ball total in the following draws.
6/15 * 4/14 * 5/13 = ?
3 balls are drawn successively from a box containing 6red,4 white and 5 blue balls.Find the probability that they are drawn in order red,white and blue if:(a)each ball is replaced.(b)balls are not replaced
3 answers
one bag contains 4 white balls,2 black balls.another bag contains 3 white balls 5 black balls.if one ball is drawn from each bag. find that
a) both are white?
b) both are black?
c)one is white and one is black?
a) both are white?
b) both are black?
c)one is white and one is black?
The sample point for 1st bag and 2nd bag are given by n(S1)=4+2=6, n(S2)=3+5=8, If one ball is drawn from each bag, the probability that both are white is given by: P(w1 n w2) ie, probability of 1st being white and 2nd being white. P(w1 n w2)=4/6*3/8=1/4
P(both are Black),P(B1 n B2)=2/6*5/8=5/24
P(one is W and one is B)=P(W1 n B2) or P(B1 n W2)=(4/6*5/8)+(2/6*3/8)=13/24. NB: "n" is used as interception which means multiplying and "or" is the union which means addition.
P(both are Black),P(B1 n B2)=2/6*5/8=5/24
P(one is W and one is B)=P(W1 n B2) or P(B1 n W2)=(4/6*5/8)+(2/6*3/8)=13/24. NB: "n" is used as interception which means multiplying and "or" is the union which means addition.