If the balls are not replaced you are dealing with dependent events, that is, the third event depends on what happened in the first, and the second depends on what happened first. So ...
prob(red, then white, then blue) = (6/15)(4/14)(5/13) = ...
If the balls are replaced, they are independent events. In this case the denominators all remain at 15
3 balls are drawn successively from a box containing 6red,4 white and 5 blue balls.Find the probability that they are drawn in order red,white and blue if:(a)each ball is replaced.(b)balls are not replaced
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