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3. An isosceles triangle has sides length xcm xcm and 9cm.

B its perimeter is less than 24 and x is a whole number.
I find the lowest value of x.
II find the highest value of x

8 answers

x+x+9 < 24
2x < 15
x < 7.5
so, x <= 7

The sides of length x must each be > 9/2, so x >= 5

5 <= x <= 7

what is the answer?

Answers

maths

2×x+9<24=2x+9÷2<24÷2=2x+9<12

X+x+9<24
2x<15
x<7 1/2
Lowest value 0
Highest 7

X+x+9<24
2x<15

5

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