3.0 moles each of carbon monoxide, hydrogen, and carbon are placed in a 2.0 liter vessel and allowed to come to equilibrium according to the equation: CO(g)+H2(g)-->C(s)+H20(g)

if the equilibrium constant at the temperature of the experiment is 4.0, what is the equilibrium concentration of water vapor?

4 answers

3.0 mols/2.0 L = 1.5M
..........CO + H2 ==> C + H2O
initial..1.5..1.5....1.5...0
change....-x...-x.....x....x
equil...1.5-x..1.5-x..x....x

Kc = 4.0 = (H2O)/(C0)(H2O)
Substitute from the ICE chart into the Kc expression and solve for x.

[H2O]=.81

[H2O]=1M

H2O = 9M