let √x = y
then:
2y^2 - 5y + 2 = 0
(2y -1)(y -2) = 0
y = 1/2 or y = 2
√x = 1/2 ----> x = 1/4
or
√x = 2 ------> x = 4
or
2x+2 = 5√x
square both sides:
4x^2 + 8x + 4 = 25x
4x^2 - 17x + 4 = 0
(x - 4)(4x - 1) =0
x = 4 or x = 1/4
btw, in both solutions, my answers have to verified since we used squaring the the process.
Luckily both answers work.
2x−5√x+2=0
quadratic equations
3 answers
Ty! :)
or, just factor it:
(√x-2)(2√x-1) = 0
√x = 2 or 1/2
(√x-2)(2√x-1) = 0
√x = 2 or 1/2